Search a number
-
+
132032511240101 is a prime number
BaseRepresentation
bin11110000001010100110110…
…111011100110011110100101
3122022111011222201111020220122
4132001110312323212132211
5114301210040334140401
61144450522011411325
736545014466200223
oct3601246673463645
9568434881436818
10132032511240101
113908474557298a
1212984950a53b45
1358897c6547c24
14248659c7d1b13
15103e70689b21b
hex781536ee67a5

132032511240101 has 2 divisors, whose sum is σ = 132032511240102. Its totient is φ = 132032511240100.

The previous prime is 132032511240061. The next prime is 132032511240137. The reversal of 132032511240101 is 101042115230231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112030158424900 + 20002352815201 = 10584430^2 + 4472399^2 .

It is a cyclic number.

It is not a de Polignac number, because 132032511240101 - 246 = 61663767062437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132032511242101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016255620050 + 66016255620051.

It is an arithmetic number, because the mean of its divisors is an integer number (66016255620051).

Almost surely, 2132032511240101 is an apocalyptic number.

It is an amenable number.

132032511240101 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032511240101 is an equidigital number, since it uses as much as digits as its factorization.

132032511240101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 132032511240101 its reverse (101042115230231), we get a palindrome (233074626470332).

The spelling of 132032511240101 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred eleven million, two hundred forty thousand, one hundred one".