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132033503402011 = 325999405011989
BaseRepresentation
bin11110000001010101110010…
…000100011001100000011011
3122022111021112212102022012001
4132001111302010121200123
5114301214103332331021
61144451204253101431
736545051204344441
oct3601256204314033
9568437485368161
10132033503402011
1139085104622902
1212984b89187877
135889923c6c593
14248665449cb91
15103e763a30091
hex78157211981b

132033503402011 has 4 divisors (see below), whose sum is σ = 132033908740000. Its totient is φ = 132033098064024.

The previous prime is 132033503401993. The next prime is 132033503402093. The reversal of 132033503402011 is 110204305330231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132033503402011 - 229 = 132032966531099 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132033503406011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202179996 + ... + 202831993.

It is an arithmetic number, because the mean of its divisors is an integer number (33008477185000).

Almost surely, 2132033503402011 is an apocalyptic number.

132033503402011 is a deficient number, since it is larger than the sum of its proper divisors (405337989).

132033503402011 is an equidigital number, since it uses as much as digits as its factorization.

132033503402011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 405337988.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 132033503402011 its reverse (110204305330231), we get a palindrome (242237808732242).

The spelling of 132033503402011 in words is "one hundred thirty-two trillion, thirty-three billion, five hundred three million, four hundred two thousand, eleven".

Divisors: 1 325999 405011989 132033503402011