132033543113455 has 4 divisors (see below), whose sum is σ = 158440251736152. Its totient is φ = 105626834490760.

The previous prime is 132033543113443. The next prime is 132033543113473. The reversal of 132033543113455 is 554311345330231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 132033543113455 - 2⁹ = 132033543112943 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13203354311341 + ... + 13203354311350.

It is an arithmetic number, because the mean of its divisors is an integer number (39610062934038).

Almost surely, 2^{132033543113455} is an apocalyptic number.

132033543113455 is a deficient number, since it is larger than the sum of its proper divisors (26406708622697).

132033543113455 is an equidigital number, since it uses as much as digits as its factorization.

132033543113455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26406708622696.

The product of its (nonzero) digits is 972000, while the sum is 43.

Adding to 132033543113455 its reverse (554311345330231), we get a palindrome (686344888443686).

The spelling of 132033543113455 in words is "one hundred thirty-two trillion, thirty-three billion, five hundred forty-three million, one hundred thirteen thousand, four hundred fifty-five".