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132034325411 = 532491213687
BaseRepresentation
bin111101011110111011…
…0111110101110100011
3110121210200212200110102
41322331312332232203
54130401241403121
6140353345453015
712352635151142
oct1727566765643
9417720780412
10132034325411
1150aa4a309aa
122170a04116b
13c5b24a9891
14656773b759
15367b75690b
hex1ebddbeba3

132034325411 has 4 divisors (see below), whose sum is σ = 134525539152. Its totient is φ = 129543111672.

The previous prime is 132034325393. The next prime is 132034325413. The reversal of 132034325411 is 114523430231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132034325411 - 214 = 132034309027 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132034325413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1245606791 + ... + 1245606896.

It is an arithmetic number, because the mean of its divisors is an integer number (33631384788).

Almost surely, 2132034325411 is an apocalyptic number.

132034325411 is a deficient number, since it is larger than the sum of its proper divisors (2491213741).

132034325411 is an equidigital number, since it uses as much as digits as its factorization.

132034325411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2491213740.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 132034325411 its reverse (114523430231), we get a palindrome (246557755642).

The spelling of 132034325411 in words is "one hundred thirty-two billion, thirty-four million, three hundred twenty-five thousand, four hundred eleven".

Divisors: 1 53 2491213687 132034325411