Base | Representation |
---|---|
bin | 11000100101111110… |
… | …11001001111000101 |
3 | 1021002011201210222210 |
4 | 30102333121033011 |
5 | 204020044311323 |
6 | 10022101014033 |
7 | 645123661605 |
oct | 142277311705 |
9 | 37064653883 |
10 | 13203510213 |
11 | 5666045713 |
12 | 26859b4319 |
13 | 13255b794a |
14 | 8d37c2c05 |
15 | 524251293 |
hex | 312fd93c5 |
13203510213 has 4 divisors (see below), whose sum is σ = 17604680288. Its totient is φ = 8802340140.
The previous prime is 13203510167. The next prime is 13203510217. The reversal of 13203510213 is 31201530231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13203510213 - 216 = 13203444677 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13203510213.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13203510217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200585033 + ... + 2200585038.
It is an arithmetic number, because the mean of its divisors is an integer number (4401170072).
Almost surely, 213203510213 is an apocalyptic number.
It is an amenable number.
13203510213 is a deficient number, since it is larger than the sum of its proper divisors (4401170075).
13203510213 is an equidigital number, since it uses as much as digits as its factorization.
13203510213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4401170074.
The product of its (nonzero) digits is 540, while the sum is 21.
The spelling of 13203510213 in words is "thirteen billion, two hundred three million, five hundred ten thousand, two hundred thirteen".
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