13203551404041 has 8 divisors (see below), whose sum is σ = 17936900020800. Its totient is φ = 8636285194992.

The previous prime is 13203551404039. The next prime is 13203551404063. The reversal of 13203551404041 is 14040415530231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13203551404041 - 2¹ = 13203551404039 is a prime.

It is a super-2 number, since 2×13203551404041² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13203551403993 and 13203551404011.

It is not an unprimeable number, because it can be changed into a prime (13203551404741) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41520601741 + ... + 41520602058.

It is an arithmetic number, because the mean of its divisors is an integer number (2242112502600).

Almost surely, 2^{13203551404041} is an apocalyptic number.

It is an amenable number.

13203551404041 is a deficient number, since it is larger than the sum of its proper divisors (4733348616759).

13203551404041 is an equidigital number, since it uses as much as digits as its factorization.

13203551404041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83041203855.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13203551404041 its reverse (14040415530231), we get a palindrome (27243966934272).

The spelling of 13203551404041 in words is "thirteen trillion, two hundred three billion, five hundred fifty-one million, four hundred four thousand, forty-one".