1320401311253 has 4 divisors (see below), whose sum is σ = 1322109463788. Its totient is φ = 1318693158720.

The previous prime is 1320401311231. The next prime is 1320401311259. The reversal of 1320401311253 is 3521131040231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 777795233329 + 542606077924 = 881927^2 + 736618^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320401311253 - 2⁸ = 1320401310997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320401311259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 854075108 + ... + 854076653.

It is an arithmetic number, because the mean of its divisors is an integer number (330527365947).

Almost surely, 2^{1320401311253} is an apocalyptic number.

It is an amenable number.

1320401311253 is a deficient number, since it is larger than the sum of its proper divisors (1708152535).

1320401311253 is an equidigital number, since it uses as much as digits as its factorization.

1320401311253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1708152534.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 1320401311253 its reverse (3521131040231), we get a palindrome (4841532351484).

The spelling of 1320401311253 in words is "one trillion, three hundred twenty billion, four hundred one million, three hundred eleven thousand, two hundred fifty-three".