Base | Representation |
---|---|
bin | 1100000000100101001011… |
… | …1101111011100010001111 |
3 | 1201202022010220222202201001 |
4 | 3000021102331323202033 |
5 | 3212314020041344010 |
6 | 44025520055201131 |
7 | 2531652303225613 |
oct | 300112275734217 |
9 | 51668126882631 |
10 | 13204121434255 |
11 | 4230922356504 |
12 | 15930696761a7 |
13 | 74a1b2b0598b |
14 | 33912362b343 |
15 | 17d70986bc3a |
hex | c0252f7b88f |
13204121434255 has 16 divisors (see below), whose sum is σ = 16357344079104. Its totient is φ = 10221751203840.
The previous prime is 13204121434253. The next prime is 13204121434267. The reversal of 13204121434255 is 55243412140231.
13204121434255 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13204121434255 - 21 = 13204121434253 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13204121434253) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1305234 + ... + 5302063.
It is an arithmetic number, because the mean of its divisors is an integer number (1022334004944).
Almost surely, 213204121434255 is an apocalyptic number.
13204121434255 is a deficient number, since it is larger than the sum of its proper divisors (3153222644849).
13204121434255 is a wasteful number, since it uses less digits than its factorization.
13204121434255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6620226.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 13204121434255 its reverse (55243412140231), we get a palindrome (68447533574486).
The spelling of 13204121434255 in words is "thirteen trillion, two hundred four billion, one hundred twenty-one million, four hundred thirty-four thousand, two hundred fifty-five".
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