Base | Representation |
---|---|
bin | 11000100110000100… |
… | …00111101000010111 |
3 | 1021002020002002212011 |
4 | 30103002013220113 |
5 | 204020240141120 |
6 | 10022124205051 |
7 | 645133025305 |
oct | 142302075027 |
9 | 37066062764 |
10 | 13204224535 |
11 | 5666493367 |
12 | 2686099787 |
13 | 13257a7b18 |
14 | 8d392b275 |
15 | 524342c5a |
hex | 313087a17 |
13204224535 has 4 divisors (see below), whose sum is σ = 15845069448. Its totient is φ = 10563379624.
The previous prime is 13204224533. The next prime is 13204224559. The reversal of 13204224535 is 53542240231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13204224535 - 21 = 13204224533 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13204224497 and 13204224506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13204224533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320422449 + ... + 1320422458.
It is an arithmetic number, because the mean of its divisors is an integer number (3961267362).
Almost surely, 213204224535 is an apocalyptic number.
13204224535 is a deficient number, since it is larger than the sum of its proper divisors (2640844913).
13204224535 is an equidigital number, since it uses as much as digits as its factorization.
13204224535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2640844912.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 13204224535 its reverse (53542240231), we get a palindrome (66746464766).
The spelling of 13204224535 in words is "thirteen billion, two hundred four million, two hundred twenty-four thousand, five hundred thirty-five".
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