1320433133601 has 4 divisors (see below), whose sum is σ = 1760577511472. Its totient is φ = 880288755732.

The previous prime is 1320433133587. The next prime is 1320433133627. The reversal of 1320433133601 is 1063313340231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-1320433133601 is a prime.

It is a super-2 number, since 2×1320433133601² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1320433133651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220072188931 + ... + 220072188936.

It is an arithmetic number, because the mean of its divisors is an integer number (440144377868).

Almost surely, 2^{1320433133601} is an apocalyptic number.

It is an amenable number.

1320433133601 is a deficient number, since it is larger than the sum of its proper divisors (440144377871).

1320433133601 is an equidigital number, since it uses as much as digits as its factorization.

1320433133601 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440144377870.

The product of its (nonzero) digits is 11664, while the sum is 30.

Adding to 1320433133601 its reverse (1063313340231), we get a palindrome (2383746473832).

The spelling of 1320433133601 in words is "one trillion, three hundred twenty billion, four hundred thirty-three million, one hundred thirty-three thousand, six hundred one".