Base | Representation |
---|---|
bin | 111101011111001100… |
… | …1100111001011110111 |
3 | 110121211022221220222022 |
4 | 1322332121213023313 |
5 | 4130411102412043 |
6 | 140354312223355 |
7 | 12353105262326 |
oct | 1727631471367 |
9 | 417738856868 |
10 | 132043404023 |
11 | 50aaa071893 |
12 | 2171109ab5b |
13 | c5b4337c3b |
14 | 6568a220bd |
15 | 367c44b868 |
hex | 1ebe6672f7 |
132043404023 has 4 divisors (see below), whose sum is σ = 134281427880. Its totient is φ = 129805380168.
The previous prime is 132043404011. The next prime is 132043404029. The reversal of 132043404023 is 320404340231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132043404023 - 226 = 131976295159 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132043403983 and 132043404001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132043404029) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1119011840 + ... + 1119011957.
It is an arithmetic number, because the mean of its divisors is an integer number (33570356970).
Almost surely, 2132043404023 is an apocalyptic number.
132043404023 is a deficient number, since it is larger than the sum of its proper divisors (2238023857).
132043404023 is an equidigital number, since it uses as much as digits as its factorization.
132043404023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2238023856.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 132043404023 its reverse (320404340231), we get a palindrome (452447744254).
The spelling of 132043404023 in words is "one hundred thirty-two billion, forty-three million, four hundred four thousand, twenty-three".
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