132044101431133 has 4 divisors (see below), whose sum is σ = 138993790980160. Its totient is φ = 125094411882108.

The previous prime is 132044101431131. The next prime is 132044101431157. The reversal of 132044101431133 is 331134101440231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132044101431133 - 2¹ = 132044101431131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132044101431095 and 132044101431104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132044101431131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3474844774485 + ... + 3474844774522.

It is an arithmetic number, because the mean of its divisors is an integer number (34748447745040).

Almost surely, 2^{132044101431133} is an apocalyptic number.

It is an amenable number.

132044101431133 is a deficient number, since it is larger than the sum of its proper divisors (6949689549027).

132044101431133 is an equidigital number, since it uses as much as digits as its factorization.

132044101431133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6949689549026.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 132044101431133 its reverse (331134101440231), we get a palindrome (463178202871364).

The spelling of 132044101431133 in words is "one hundred thirty-two trillion, forty-four billion, one hundred one million, four hundred thirty-one thousand, one hundred thirty-three".