132044304430111 has 4 divisors (see below), whose sum is σ = 132044512122432. Its totient is φ = 132044096737792.

The previous prime is 132044304430063. The next prime is 132044304430121. The reversal of 132044304430111 is 111034403440231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132044304430111 - 2¹¹ = 132044304428063 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132044304430121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102889570 + ... + 104165023.

It is an arithmetic number, because the mean of its divisors is an integer number (33011128030608).

Almost surely, 2^{132044304430111} is an apocalyptic number.

132044304430111 is a deficient number, since it is larger than the sum of its proper divisors (207692321).

132044304430111 is an equidigital number, since it uses as much as digits as its factorization.

132044304430111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207692320.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 132044304430111 its reverse (111034403440231), we get a palindrome (243078707870342).

The spelling of 132044304430111 in words is "one hundred thirty-two trillion, forty-four billion, three hundred four million, four hundred thirty thousand, one hundred eleven".