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132044320320403 = 555472377163849
BaseRepresentation
bin11110000001011111110110…
…110011101010101110010011
3122022112022110201100200200011
4132001133312303222232103
5114301403232000223103
61144500153501135351
736545613231545611
oct3601376663525623
9568468421320604
10132044320320403
1139089755483787
12129870a785a557
13588a958c844ca
142486d9cd126b1
15103eb984a7d6d
hex7817f6ceab93

132044320320403 has 4 divisors (see below), whose sum is σ = 132046697539800. Its totient is φ = 132041943101008.

The previous prime is 132044320320343. The next prime is 132044320320421. The reversal of 132044320320403 is 304023023440231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132044320320403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132044320320103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1188526378 + ... + 1188637471.

It is an arithmetic number, because the mean of its divisors is an integer number (33011674384950).

Almost surely, 2132044320320403 is an apocalyptic number.

132044320320403 is a deficient number, since it is larger than the sum of its proper divisors (2377219397).

132044320320403 is an equidigital number, since it uses as much as digits as its factorization.

132044320320403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2377219396.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 132044320320403 its reverse (304023023440231), we get a palindrome (436067343760634).

The spelling of 132044320320403 in words is "one hundred thirty-two trillion, forty-four billion, three hundred twenty million, three hundred twenty thousand, four hundred three".

Divisors: 1 55547 2377163849 132044320320403