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132044330413111 = 359367811505329
BaseRepresentation
bin11110000001011111110111…
…011010001010110000110111
3122022112022111102100110021011
4132001133313122022300313
5114301403242041204421
61144500154501333051
736545613413412454
oct3601376732126067
9568468442313234
10132044330413111
1139089760147566
12129870ab107187
13588a95b0a931c
142486da03bc82b
15103eb992ed4e1
hex7817f768ac37

132044330413111 has 4 divisors (see below), whose sum is σ = 132412141918800. Its totient is φ = 131676518907424.

The previous prime is 132044330413001. The next prime is 132044330413159. The reversal of 132044330413111 is 111314033440231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132044330413111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132044330423111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183905752306 + ... + 183905753023.

It is an arithmetic number, because the mean of its divisors is an integer number (33103035479700).

Almost surely, 2132044330413111 is an apocalyptic number.

132044330413111 is a deficient number, since it is larger than the sum of its proper divisors (367811505689).

132044330413111 is an equidigital number, since it uses as much as digits as its factorization.

132044330413111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 367811505688.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 132044330413111 its reverse (111314033440231), we get a palindrome (243358363853342).

The spelling of 132044330413111 in words is "one hundred thirty-two trillion, forty-four billion, three hundred thirty million, four hundred thirteen thousand, one hundred eleven".

Divisors: 1 359 367811505329 132044330413111