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13205103005551 = 21872360373637
BaseRepresentation
bin1100000000101000110101…
…1110010100111101101111
31201202101200022222202101111
43000022031132110331233
53212323022332134201
644030201321452451
72532015522363532
oct300121536247557
951671608882344
1013205103005551
114231286432556
1215932a2341127
1374a30b28c9b2
143391b7b3ca19
1517d765b0cb51
hexc028d794f6f

13205103005551 has 4 divisors (see below), whose sum is σ = 13205163597912. Its totient is φ = 13205042413192.

The previous prime is 13205103005477. The next prime is 13205103005581. The reversal of 13205103005551 is 15550030150231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13205103005551 - 221 = 13205100908399 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13205103005581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29968096 + ... + 30405541.

It is an arithmetic number, because the mean of its divisors is an integer number (3301290899478).

Almost surely, 213205103005551 is an apocalyptic number.

13205103005551 is a deficient number, since it is larger than the sum of its proper divisors (60592361).

13205103005551 is an equidigital number, since it uses as much as digits as its factorization.

13205103005551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60592360.

The product of its (nonzero) digits is 11250, while the sum is 31.

Adding to 13205103005551 its reverse (15550030150231), we get a palindrome (28755133155782).

The spelling of 13205103005551 in words is "thirteen trillion, two hundred five billion, one hundred three million, five thousand, five hundred fifty-one".

Divisors: 1 218723 60373637 13205103005551