Base | Representation |
---|---|
bin | 10011001101110100110… |
… | …011001101001001101111 |
3 | 11200020110221002001212020 |
4 | 103031310303031021233 |
5 | 133113403210241033 |
6 | 2450345213241223 |
7 | 164255403251331 |
oct | 23156463151157 |
9 | 4606427061766 |
10 | 1320514540143 |
11 | 46a0330398a7 |
12 | 193b11793213 |
13 | 976a72783a6 |
14 | 47cadd2d451 |
15 | 24539e2c6b3 |
hex | 13374ccd26f |
1320514540143 has 4 divisors (see below), whose sum is σ = 1760686053528. Its totient is φ = 880343026760.
The previous prime is 1320514540133. The next prime is 1320514540193. The reversal of 1320514540143 is 3410454150231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1320514540143 - 220 = 1320513491567 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320514540133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220085756688 + ... + 220085756693.
It is an arithmetic number, because the mean of its divisors is an integer number (440171513382).
Almost surely, 21320514540143 is an apocalyptic number.
1320514540143 is a deficient number, since it is larger than the sum of its proper divisors (440171513385).
1320514540143 is an equidigital number, since it uses as much as digits as its factorization.
1320514540143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 440171513384.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 1320514540143 its reverse (3410454150231), we get a palindrome (4730968690374).
The spelling of 1320514540143 in words is "one trillion, three hundred twenty billion, five hundred fourteen million, five hundred forty thousand, one hundred forty-three".
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