Base | Representation |
---|---|
bin | 11110000001101000011010… |
… | …010001101000001010110011 |
3 | 122022120012011211112120122022 |
4 | 132001220122101220022303 |
5 | 114302031034324431121 |
6 | 1144504313131302055 |
7 | 36546356651643215 |
oct | 3601503221501263 |
9 | 568505154476568 |
10 | 132053505311411 |
11 | 39092639136442 |
12 | 12988a2b8aa92b |
13 | 588b790b65328 |
14 | 24875d0b205b5 |
15 | 1040034a26aab |
hex | 781a1a4682b3 |
132053505311411 has 4 divisors (see below), whose sum is σ = 132737720365032. Its totient is φ = 131369290257792.
The previous prime is 132053505311407. The next prime is 132053505311417. The reversal of 132053505311411 is 114113505350231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132053505311411 - 22 = 132053505311407 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132053505311417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342107526521 + ... + 342107526906.
It is an arithmetic number, because the mean of its divisors is an integer number (33184430091258).
Almost surely, 2132053505311411 is an apocalyptic number.
132053505311411 is a deficient number, since it is larger than the sum of its proper divisors (684215053621).
132053505311411 is an equidigital number, since it uses as much as digits as its factorization.
132053505311411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 684215053620.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 132053505311411 in words is "one hundred thirty-two trillion, fifty-three billion, five hundred five million, three hundred eleven thousand, four hundred eleven".
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