Base | Representation |
---|---|
bin | 11110000001101000011010… |
… | …010001101000001010101111 |
3 | 122022120012011211112120122011 |
4 | 132001220122101220022233 |
5 | 114302031034324431112 |
6 | 1144504313131302051 |
7 | 36546356651643211 |
oct | 3601503221501257 |
9 | 568505154476564 |
10 | 132053505311407 |
11 | 39092639136439 |
12 | 12988a2b8aa927 |
13 | 588b790b65324 |
14 | 24875d0b205b1 |
15 | 1040034a26aa7 |
hex | 781a1a4682af |
132053505311407 has 2 divisors, whose sum is σ = 132053505311408. Its totient is φ = 132053505311406.
The previous prime is 132053505311393. The next prime is 132053505311417. The reversal of 132053505311407 is 704113505350231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132053505311407 - 27 = 132053505311279 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132053505311407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132053505311417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026752655703 + 66026752655704.
It is an arithmetic number, because the mean of its divisors is an integer number (66026752655704).
Almost surely, 2132053505311407 is an apocalyptic number.
132053505311407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132053505311407 is an equidigital number, since it uses as much as digits as its factorization.
132053505311407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 189000, while the sum is 40.
The spelling of 132053505311407 in words is "one hundred thirty-two trillion, fifty-three billion, five hundred five million, three hundred eleven thousand, four hundred seven".
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