13205605041 has 10 divisors (see below), whose sum is σ = 19726891602. Its totient is φ = 8803736640.

The previous prime is 13205605031. The next prime is 13205605057. The reversal of 13205605041 is 14050650231.

13205605041 is a `hidden beast` number, since 13 + 2 + 0 + 5 + 605 + 0 + 41 = 666.

It can be written as a sum of positive squares in only one way, i.e., 8625022641 + 4580582400 = 92871^2 + 67680^2 .

It is not a de Polignac number, because 13205605041 - 2¹³ = 13205596849 is a prime.

It is a super-3 number, since 3×13205605041³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13205604996 and 13205605014.

It is not an unprimeable number, because it can be changed into a prime (13205605001) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 81516000 + ... + 81516161.

Almost surely, 2^13205605041 is an apocalyptic number.

It is an amenable number.

13205605041 is a deficient number, since it is larger than the sum of its proper divisors (6521286561).

13205605041 is an equidigital number, since it uses as much as digits as its factorization.

13205605041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163032173 (or 163032164 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

The spelling of 13205605041 in words is "thirteen billion, two hundred five million, six hundred five thousand, forty-one".