Base | Representation |
---|---|
bin | 1100000000101110100010… |
… | …1100001000101101001111 |
3 | 1201202112121222121102002011 |
4 | 3000023220230020231033 |
5 | 3212334141114231030 |
6 | 44031013230242051 |
7 | 2532101454202165 |
oct | 300135054105517 |
9 | 51675558542064 |
10 | 13206633352015 |
11 | 42319a125a4a4 |
12 | 159364a956327 |
13 | 74a4c334884c |
14 | 3392c10a1235 |
15 | 17d80514db2a |
hex | c02e8b08b4f |
13206633352015 has 4 divisors (see below), whose sum is σ = 15847960022424. Its totient is φ = 10565306681608.
The previous prime is 13206633352007. The next prime is 13206633352037. The reversal of 13206633352015 is 51025333660231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13206633352015 - 23 = 13206633352007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320663335197 + ... + 1320663335206.
It is an arithmetic number, because the mean of its divisors is an integer number (3961990005606).
Almost surely, 213206633352015 is an apocalyptic number.
13206633352015 is a deficient number, since it is larger than the sum of its proper divisors (2641326670409).
13206633352015 is an equidigital number, since it uses as much as digits as its factorization.
13206633352015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2641326670408.
The product of its (nonzero) digits is 291600, while the sum is 40.
The spelling of 13206633352015 in words is "thirteen trillion, two hundred six billion, six hundred thirty-three million, three hundred fifty-two thousand, fifteen".
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