Base | Representation |
---|---|
bin | 1100000000111000111100… |
… | …0111110000111011001101 |
3 | 1201202210211120201221100220 |
4 | 3000032033013300323031 |
5 | 3212410400424044433 |
6 | 44032154254141553 |
7 | 2532230611054245 |
oct | 300161707607315 |
9 | 51683746657326 |
10 | 13209425612493 |
11 | 42330a4431090 |
12 | 15940a9ab18b9 |
13 | 74a849996096 |
14 | 3394a7c6cb25 |
15 | 17d91a35a2b3 |
hex | c038f1f0ecd |
13209425612493 has 16 divisors (see below), whose sum is σ = 20343928216896. Its totient is φ = 7534788227840.
The previous prime is 13209425612483. The next prime is 13209425612501. The reversal of 13209425612493 is 39421652490231.
13209425612493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13209425612493 - 213 = 13209425604301 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13209425612483) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11773106046 + ... + 11773107167.
It is an arithmetic number, because the mean of its divisors is an integer number (1271495513556).
Almost surely, 213209425612493 is an apocalyptic number.
It is an amenable number.
13209425612493 is a deficient number, since it is larger than the sum of its proper divisors (7134502604403).
13209425612493 is a wasteful number, since it uses less digits than its factorization.
13209425612493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23546213244.
The product of its (nonzero) digits is 2799360, while the sum is 51.
The spelling of 13209425612493 in words is "thirteen trillion, two hundred nine billion, four hundred twenty-five million, six hundred twelve thousand, four hundred ninety-three".
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