Base | Representation |
---|---|
bin | 11110000010010011101111… |
… | …100000000011000000011011 |
3 | 122022201122021101022001210021 |
4 | 132002103233200003000123 |
5 | 114303311331232430243 |
6 | 1144541530030331311 |
7 | 36552624642631246 |
oct | 3602235740030033 |
9 | 568648241261707 |
10 | 132100032311323 |
11 | 3910034444308a |
12 | 12995a55659b37 |
13 | 5892c9722cccb |
14 | 24899660c025d |
15 | 10413595446ed |
hex | 7824ef80301b |
132100032311323 has 8 divisors (see below), whose sum is σ = 134347506969600. Its totient is φ = 129852840688488.
The previous prime is 132100032311297. The next prime is 132100032311347. The reversal of 132100032311323 is 323113230001231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132100032311323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132100032311363) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69817363 + ... + 71684476.
It is an arithmetic number, because the mean of its divisors is an integer number (16793438371200).
Almost surely, 2132100032311323 is an apocalyptic number.
132100032311323 is a deficient number, since it is larger than the sum of its proper divisors (2247474658277).
132100032311323 is a wasteful number, since it uses less digits than its factorization.
132100032311323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 141517721.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 132100032311323 its reverse (323113230001231), we get a palindrome (455213262312554).
The spelling of 132100032311323 in words is "one hundred thirty-two trillion, one hundred billion, thirty-two million, three hundred eleven thousand, three hundred twenty-three".
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