13210025400001 has 4 divisors (see below), whose sum is σ = 13289127348672. Its totient is φ = 13130923451332.

The previous prime is 13210025399971. The next prime is 13210025400043. The reversal of 13210025400001 is 10000452001231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13210025400001 - 2¹⁵ = 13210025367233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13210025100001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39550974085 + ... + 39550974418.

It is an arithmetic number, because the mean of its divisors is an integer number (3322281837168).

Almost surely, 2^{13210025400001} is an apocalyptic number.

It is an amenable number.

13210025400001 is a deficient number, since it is larger than the sum of its proper divisors (79101948671).

13210025400001 is an equidigital number, since it uses as much as digits as its factorization.

13210025400001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79101948670.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 13210025400001 its reverse (10000452001231), we get a palindrome (23210477401232).

The spelling of 13210025400001 in words is "thirteen trillion, two hundred ten billion, twenty-five million, four hundred thousand, one".