Base | Representation |
---|---|
bin | 1100000000111011001011… |
… | …0110101000001011100001 |
3 | 1201202212101100210001121221 |
4 | 3000032302312220023201 |
5 | 3212413112411200001 |
6 | 44032333551215041 |
7 | 2532251510450242 |
oct | 300166266501341 |
9 | 51685340701557 |
10 | 13210025100001 |
11 | 4233381869a04 |
12 | 1594236817481 |
13 | 74a913c42612 |
14 | 339523720cc9 |
15 | 17d952cc61a1 |
hex | c03b2da82e1 |
13210025100001 has 2 divisors, whose sum is σ = 13210025100002. Its totient is φ = 13210025100000.
The previous prime is 13210025099989. The next prime is 13210025100011. The reversal of 13210025100001 is 10000152001231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11199865424400 + 2010159675601 = 3346620^2 + 1417801^2 .
It is a cyclic number.
It is not a de Polignac number, because 13210025100001 - 241 = 11011001844449 is a prime.
It is not a weakly prime, because it can be changed into another prime (13210025100011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605012550000 + 6605012550001.
It is an arithmetic number, because the mean of its divisors is an integer number (6605012550001).
Almost surely, 213210025100001 is an apocalyptic number.
It is an amenable number.
13210025100001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13210025100001 is an equidigital number, since it uses as much as digits as its factorization.
13210025100001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 13210025100001 its reverse (10000152001231), we get a palindrome (23210177101232).
The spelling of 13210025100001 in words is "thirteen trillion, two hundred ten billion, twenty-five million, one hundred thousand, one".
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