Base | Representation |
---|---|
bin | 1100000000111011001011… |
… | …0111110001011011100011 |
3 | 1201202212101101100022012022 |
4 | 3000032302313301123203 |
5 | 3212413113000300120 |
6 | 44032334001452055 |
7 | 2532251513140052 |
oct | 300166267613343 |
9 | 51685341308168 |
10 | 13210025400035 |
11 | 4233381a54372 |
12 | 159423694102b |
13 | 74a914019059 |
14 | 33952379c399 |
15 | 17d952d35025 |
hex | c03b2df16e3 |
13210025400035 has 16 divisors (see below), whose sum is σ = 15859384247520. Its totient is φ = 10563118556160.
The previous prime is 13210025399971. The next prime is 13210025400043. The reversal of 13210025400035 is 53000452001231.
It is a happy number.
It is not a de Polignac number, because 13210025400035 - 26 = 13210025399971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13210025399977 and 13210025400013.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 168798515 + ... + 168876755.
It is an arithmetic number, because the mean of its divisors is an integer number (991211515470).
Almost surely, 213210025400035 is an apocalyptic number.
13210025400035 is a deficient number, since it is larger than the sum of its proper divisors (2649358847485).
13210025400035 is a wasteful number, since it uses less digits than its factorization.
13210025400035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93478.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 13210025400035 its reverse (53000452001231), we get a palindrome (66210477401266).
The spelling of 13210025400035 in words is "thirteen trillion, two hundred ten billion, twenty-five million, four hundred thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •