Base | Representation |
---|---|
bin | 11000100110110010… |
… | …10101110110110001 |
3 | 1021002122112101110000 |
4 | 30103121111312301 |
5 | 204023314441423 |
6 | 10022502500213 |
7 | 645235541325 |
oct | 142331256661 |
9 | 37078471400 |
10 | 13210312113 |
11 | 5669971019 |
12 | 2688134669 |
13 | 1326b2993b |
14 | 8d4673985 |
15 | 524b46843 |
hex | 313655db1 |
13210312113 has 20 divisors (see below), whose sum is σ = 19741316980. Its totient is φ = 8803575072.
The previous prime is 13210312103. The next prime is 13210312151. The reversal of 13210312113 is 31121301231.
It can be written as a sum of positive squares in 2 ways, for example, as 8087045184 + 5123266929 = 89928^2 + 71577^2 .
It is not a de Polignac number, because 13210312113 - 25 = 13210312081 is a prime.
It is a super-2 number, since 2×132103121132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13210312103) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 197403 + ... + 255711.
It is an arithmetic number, because the mean of its divisors is an integer number (987065849).
Almost surely, 213210312113 is an apocalyptic number.
It is an amenable number.
13210312113 is a deficient number, since it is larger than the sum of its proper divisors (6531004867).
13210312113 is an equidigital number, since it uses as much as digits as its factorization.
13210312113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61118 (or 61109 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 13210312113 its reverse (31121301231), we get a palindrome (44331613344).
The spelling of 13210312113 in words is "thirteen billion, two hundred ten million, three hundred twelve thousand, one hundred thirteen".
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