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13210312114 = 27193030367
BaseRepresentation
bin11000100110110010…
…10101110110110010
31021002122112101110001
430103121111312302
5204023314441424
610022502500214
7645235541326
oct142331256662
937078471401
1013210312114
11566997101a
12268813466a
131326b2993c
148d4673986
15524b46844
hex313655db2

13210312114 has 8 divisors (see below), whose sum is σ = 20094559488. Its totient is φ = 6512125620.

The previous prime is 13210312103. The next prime is 13210312151. The reversal of 13210312114 is 41121301231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×132103121142 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13210312091 and 13210312100.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46515042 + ... + 46515325.

It is an arithmetic number, because the mean of its divisors is an integer number (2511819936).

Almost surely, 213210312114 is an apocalyptic number.

13210312114 is a deficient number, since it is larger than the sum of its proper divisors (6884247374).

13210312114 is an equidigital number, since it uses as much as digits as its factorization.

13210312114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93030440.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13210312114 its reverse (41121301231), we get a palindrome (54331613345).

The spelling of 13210312114 in words is "thirteen billion, two hundred ten million, three hundred twelve thousand, one hundred fourteen".

Divisors: 1 2 71 142 93030367 186060734 6605156057 13210312114