Base | Representation |
---|---|
bin | 11110000010010111001100… |
… | …100001110111011000110010 |
3 | 122022201222211211000020201111 |
4 | 132002113030201313120302 |
5 | 114303341430040142004 |
6 | 1144543342015023534 |
7 | 36553115561311615 |
oct | 3602271441673062 |
9 | 568658754006644 |
10 | 132103740552754 |
11 | 39101977671823 |
12 | 1299670b50abaa |
13 | 589343857abc9 |
14 | 2489bd87a817c |
15 | 10414c4d87a04 |
hex | 7825cc877632 |
132103740552754 has 8 divisors (see below), whose sum is σ = 206771072169600. Its totient is φ = 63180049829556.
The previous prime is 132103740552709. The next prime is 132103740552781. The reversal of 132103740552754 is 457255047301231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 132103740552698 and 132103740552707.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1435910223354 + ... + 1435910223445.
It is an arithmetic number, because the mean of its divisors is an integer number (25846384021200).
Almost surely, 2132103740552754 is an apocalyptic number.
132103740552754 is a deficient number, since it is larger than the sum of its proper divisors (74667331616846).
132103740552754 is a wasteful number, since it uses less digits than its factorization.
132103740552754 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2871820446824.
The product of its (nonzero) digits is 3528000, while the sum is 49.
Adding to 132103740552754 its reverse (457255047301231), we get a palindrome (589358787853985).
The spelling of 132103740552754 in words is "one hundred thirty-two trillion, one hundred three billion, seven hundred forty million, five hundred fifty-two thousand, seven hundred fifty-four".
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