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132104300042000 = 24531113895189923
BaseRepresentation
bin11110000010010111101101…
…111000001001011100010000
3122022202001021210210020200102
4132002113231320021130100
5114303344101302321000
61144543513322511532
736553135464014606
oct3602275570113420
9568661253706612
10132104300042000
1139102134470330
12129968469655a8
1358934c7461630
142489c4cc07876
1510415090523d5
hex7825ede09710

132104300042000 has 320 divisors, whose sum is σ = 379488903655680. Its totient is φ = 43844461056000.

The previous prime is 132104300041939. The next prime is 132104300042087. The reversal of 132104300042000 is 240003401231.

It is a super-2 number, since 2×1321043000420002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 22859039 + ... + 28048961.

It is an arithmetic number, because the mean of its divisors is an integer number (1185902823924).

Almost surely, 2132104300042000 is an apocalyptic number.

132104300042000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132104300042000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (189744451827840).

132104300042000 is an abundant number, since it is smaller than the sum of its proper divisors (247384603613680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132104300042000 is a wasteful number, since it uses less digits than its factorization.

132104300042000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5190059 (or 5190043 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 132104300042000 its reverse (240003401231), we get a palindrome (132344303443231).

The spelling of 132104300042000 in words is "one hundred thirty-two trillion, one hundred four billion, three hundred million, forty-two thousand".