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132110011152 = 2434725756663
BaseRepresentation
bin111101100001001011…
…1101100101100010000
3110121222222021220210000
41323002113230230100
54131030130324102
6140405052010000
712354544365240
oct1730227545420
9417888256700
10132110011152
11510337257a9
122172b460900
13c5c5089342
1465737ddb20
15368320701c
hex1ec25ecb10

132110011152 has 200 divisors, whose sum is σ = 438696314496. Its totient is φ = 37598183424.

The previous prime is 132110011151. The next prime is 132110011157. The reversal of 132110011152 is 251110011231.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (132110011151) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2303173 + ... + 2359835.

Almost surely, 2132110011152 is an apocalyptic number.

132110011152 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132110011152, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (219348157248).

132110011152 is an abundant number, since it is smaller than the sum of its proper divisors (306586303344).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132110011152 is a wasteful number, since it uses less digits than its factorization.

132110011152 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56947 (or 56932 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 18.

Adding to 132110011152 its reverse (251110011231), we get a palindrome (383220022383).

The spelling of 132110011152 in words is "one hundred thirty-two billion, one hundred ten million, eleven thousand, one hundred fifty-two".