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132110411012455 = 5232893339705049
BaseRepresentation
bin11110000010011101011010…
…000111101001100101100111
3122022202122001200122201012111
4132002131122013221211213
5114303444110204344310
61144550403542101451
736553443066266161
oct3602353207514547
9568678050581174
10132110411012455
113910478a9a5937
1212997a7141a887
135893c5c512395
14248a26c661931
1510417657aa28a
hex78275a1e9967

132110411012455 has 16 divisors (see below), whose sum is σ = 165430932004800. Its totient is φ = 101089687488768.

The previous prime is 132110411012453. The next prime is 132110411012479. The reversal of 132110411012455 is 554210114011231.

It is a cyclic number.

It is not a de Polignac number, because 132110411012455 - 21 = 132110411012453 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132110411012453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16525230 + ... + 23179819.

It is an arithmetic number, because the mean of its divisors is an integer number (10339433250300).

Almost surely, 2132110411012455 is an apocalyptic number.

132110411012455 is a deficient number, since it is larger than the sum of its proper divisors (33320520992345).

132110411012455 is a wasteful number, since it uses less digits than its factorization.

132110411012455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39734010.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 132110411012455 its reverse (554210114011231), we get a palindrome (686320525023686).

The spelling of 132110411012455 in words is "one hundred thirty-two trillion, one hundred ten billion, four hundred eleven million, twelve thousand, four hundred fifty-five".

Divisors: 1 5 23 115 28933 144665 665459 3327295 39705049 198525245 913216127 4566080635 1148786182717 5743930913585 26422082202491 132110411012455