Base | Representation |
---|---|
bin | 11110000010011101011010… |
… | …000111101001100101100111 |
3 | 122022202122001200122201012111 |
4 | 132002131122013221211213 |
5 | 114303444110204344310 |
6 | 1144550403542101451 |
7 | 36553443066266161 |
oct | 3602353207514547 |
9 | 568678050581174 |
10 | 132110411012455 |
11 | 3910478a9a5937 |
12 | 12997a7141a887 |
13 | 5893c5c512395 |
14 | 248a26c661931 |
15 | 10417657aa28a |
hex | 78275a1e9967 |
132110411012455 has 16 divisors (see below), whose sum is σ = 165430932004800. Its totient is φ = 101089687488768.
The previous prime is 132110411012453. The next prime is 132110411012479. The reversal of 132110411012455 is 554210114011231.
It is a cyclic number.
It is not a de Polignac number, because 132110411012455 - 21 = 132110411012453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132110411012453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16525230 + ... + 23179819.
It is an arithmetic number, because the mean of its divisors is an integer number (10339433250300).
Almost surely, 2132110411012455 is an apocalyptic number.
132110411012455 is a deficient number, since it is larger than the sum of its proper divisors (33320520992345).
132110411012455 is a wasteful number, since it uses less digits than its factorization.
132110411012455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39734010.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 132110411012455 its reverse (554210114011231), we get a palindrome (686320525023686).
The spelling of 132110411012455 in words is "one hundred thirty-two trillion, one hundred ten billion, four hundred eleven million, twelve thousand, four hundred fifty-five".
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