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1321105255433 = 17171103454183
BaseRepresentation
bin10011001110011000000…
…000100110110000001001
311200022000002121111220022
4103032120000212300021
5133121110421133213
62450523554310225
7164306135250335
oct23163000466011
94608002544808
101321105255433
1146a306525a57
12194057588375
139776c772b72
1447d2857a7c5
1524571c14308
hex13398026c09

1321105255433 has 8 divisors (see below), whose sum is σ = 1398828584448. Its totient is φ = 1243383177024.

The previous prime is 1321105255397. The next prime is 1321105255439. The reversal of 1321105255433 is 3345525011231.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1321105255433 - 26 = 1321105255369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1321105255393 and 1321105255402.

It is not an unprimeable number, because it can be changed into a prime (1321105255439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2681660 + ... + 3135842.

It is an arithmetic number, because the mean of its divisors is an integer number (174853573056).

Almost surely, 21321105255433 is an apocalyptic number.

It is an amenable number.

1321105255433 is a deficient number, since it is larger than the sum of its proper divisors (77723329015).

1321105255433 is a wasteful number, since it uses less digits than its factorization.

1321105255433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 625303.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 1321105255433 in words is "one trillion, three hundred twenty-one billion, one hundred five million, two hundred fifty-five thousand, four hundred thirty-three".

Divisors: 1 17 171103 454183 2908751 7721111 77712073849 1321105255433