132111123440231 has 8 divisors (see below), whose sum is σ = 144605870298624. Its totient is φ = 119949569831520.

The previous prime is 132111123440147. The next prime is 132111123440237. The reversal of 132111123440231 is 132044321111231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-132111123440231 is a prime.

It is a super-2 number, since 2×132111123440231² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132111123440194 and 132111123440203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132111123440237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83298311591 + ... + 83298313176.

It is an arithmetic number, because the mean of its divisors is an integer number (18075733787328).

Almost surely, 2^{132111123440231} is an apocalyptic number.

132111123440231 is a deficient number, since it is larger than the sum of its proper divisors (12494746858393).

132111123440231 is a wasteful number, since it uses less digits than its factorization.

132111123440231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166596624841.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 132111123440231 its reverse (132044321111231), we get a palindrome (264155444551462).

The spelling of 132111123440231 in words is "one hundred thirty-two trillion, one hundred eleven billion, one hundred twenty-three million, four hundred forty thousand, two hundred thirty-one".