1321113113 has 4 divisors (see below), whose sum is σ = 1321776000. Its totient is φ = 1320450228.

The previous prime is 1321113109. The next prime is 1321113223. The reversal of 1321113113 is 3113111231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3113111231 = 1723 ⋅1806797.

It is a cyclic number.

It is not a de Polignac number, because 1321113113 - 2² = 1321113109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1321113091 and 1321113100.

It is not an unprimeable number, because it can be changed into a prime (1321115113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328445 + ... + 332442.

It is an arithmetic number, because the mean of its divisors is an integer number (330444000).

Almost surely, 2^1321113113 is an apocalyptic number.

It is an amenable number.

1321113113 is a deficient number, since it is larger than the sum of its proper divisors (662887).

1321113113 is an equidigital number, since it uses as much as digits as its factorization.

1321113113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 662886.

The product of its digits is 54, while the sum is 17.

The square root of 1321113113 is about 36347.1197345814. The cubic root of 1321113113 is about 1097.2695677679.

Adding to 1321113113 its reverse (3113111231), we get a palindrome (4434224344).

The spelling of 1321113113 in words is "one billion, three hundred twenty-one million, one hundred thirteen thousand, one hundred thirteen".