Base | Representation |
---|---|
bin | 11110000010011110011110… |
… | …000100100011101011010111 |
3 | 122022202202000010211202010222 |
4 | 132002132132010203223113 |
5 | 114304003424032140003 |
6 | 1144551113025104555 |
7 | 36553513251415121 |
oct | 3602363604435327 |
9 | 568682003752128 |
10 | 132111551052503 |
11 | 391052154788a0 |
12 | 1299812b18815b |
13 | 58940b1771ba9 |
14 | 248a339c24211 |
15 | 10417d08eec38 |
hex | 78279e123ad7 |
132111551052503 has 4 divisors (see below), whose sum is σ = 144121692057288. Its totient is φ = 120101410047720.
The previous prime is 132111551052457. The next prime is 132111551052527. The reversal of 132111551052503 is 305250155111231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132111551052503 - 226 = 132111483943639 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132111551051503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6005070502376 + ... + 6005070502397.
It is an arithmetic number, because the mean of its divisors is an integer number (36030423014322).
Almost surely, 2132111551052503 is an apocalyptic number.
132111551052503 is a deficient number, since it is larger than the sum of its proper divisors (12010141004785).
132111551052503 is a wasteful number, since it uses less digits than its factorization.
132111551052503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12010141004784.
The product of its (nonzero) digits is 22500, while the sum is 35.
The spelling of 132111551052503 in words is "one hundred thirty-two trillion, one hundred eleven billion, five hundred fifty-one million, fifty-two thousand, five hundred three".
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