Base | Representation |
---|---|
bin | 1100000000111111100110… |
… | …1101111101111011010001 |
3 | 1201202222110012221001102212 |
4 | 3000033321231331323101 |
5 | 3212423031241341423 |
6 | 44033051541521505 |
7 | 2532323125155305 |
oct | 300177155757321 |
9 | 51688405831385 |
10 | 13211214012113 |
11 | 42339319921a7 |
12 | 1594508a13295 |
13 | 74aa73354000 |
14 | 3395d75a5d05 |
15 | 17d9c2371578 |
hex | c03f9b7ded1 |
13211214012113 has 32 divisors (see below), whose sum is σ = 14410766415360. Its totient is φ = 12110759781120.
The previous prime is 13211214012049. The next prime is 13211214012121. The reversal of 13211214012113 is 31121041211231.
It is not a de Polignac number, because 13211214012113 - 26 = 13211214012049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13211214012413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 214600745 + ... + 214662297.
It is an arithmetic number, because the mean of its divisors is an integer number (450336450480).
Almost surely, 213211214012113 is an apocalyptic number.
13211214012113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13211214012113 is a deficient number, since it is larger than the sum of its proper divisors (1199552403247).
13211214012113 is an equidigital number, since it uses as much as digits as its factorization.
13211214012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62266 (or 62240 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 13211214012113 its reverse (31121041211231), we get a palindrome (44332255223344).
The spelling of 13211214012113 in words is "thirteen trillion, two hundred eleven billion, two hundred fourteen million, twelve thousand, one hundred thirteen".
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