Base | Representation |
---|---|
bin | 11110000010011111000100… |
… | …110000111100010100101111 |
3 | 122022202210200101100222021122 |
4 | 132002133010300330110233 |
5 | 114304011241224100444 |
6 | 1144551301255051155 |
7 | 36553535323312424 |
oct | 3602370460742457 |
9 | 568683611328248 |
10 | 132112200221999 |
11 | 3910551895a508 |
12 | 12998290670abb |
13 | 58941860c4b5a |
14 | 248a39c129d4b |
15 | 104181c8d14ee |
hex | 7827c4c3c52f |
132112200221999 has 4 divisors (see below), whose sum is σ = 136373884100160. Its totient is φ = 127850516343840.
The previous prime is 132112200221983. The next prime is 132112200222059. The reversal of 132112200221999 is 999122002211231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 132112200221999 - 24 = 132112200221983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132112200221699) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2130841939034 + ... + 2130841939095.
It is an arithmetic number, because the mean of its divisors is an integer number (34093471025040).
Almost surely, 2132112200221999 is an apocalyptic number.
132112200221999 is a deficient number, since it is larger than the sum of its proper divisors (4261683878161).
132112200221999 is an equidigital number, since it uses as much as digits as its factorization.
132112200221999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4261683878160.
The product of its (nonzero) digits is 69984, while the sum is 44.
The spelling of 132112200221999 in words is "one hundred thirty-two trillion, one hundred twelve billion, two hundred million, two hundred twenty-one thousand, nine hundred ninety-nine".
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