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132113004343541 = 1323531431878747
BaseRepresentation
bin11110000010011111110100…
…101100011011000011110101
3122022202212202102110120122222
4132002133310230123003311
5114304014413102443131
61144551513142132125
736553564256243204
oct3602376454330365
9568685672416588
10132113004343541
11391058a0855971
1212998475a21045
13589428388ba10
14248a436c4923b
1510418682be87b
hex7827f4b1b0f5

132113004343541 has 8 divisors (see below), whose sum is σ = 142281589771104. Its totient is φ = 121945282720560.

The previous prime is 132113004343513. The next prime is 132113004343561. The reversal of 132113004343541 is 145343400311231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-132113004343541 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132113004343561) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 215633471 + ... + 216245276.

It is an arithmetic number, because the mean of its divisors is an integer number (17785198721388).

Almost surely, 2132113004343541 is an apocalyptic number.

It is an amenable number.

132113004343541 is a deficient number, since it is larger than the sum of its proper divisors (10168585427563).

132113004343541 is a wasteful number, since it uses less digits than its factorization.

132113004343541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 431902291.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 132113004343541 its reverse (145343400311231), we get a palindrome (277456404654772).

The spelling of 132113004343541 in words is "one hundred thirty-two trillion, one hundred thirteen billion, four million, three hundred forty-three thousand, five hundred forty-one".

Divisors: 1 13 23531 305903 431878747 5614423711 10162538795657 132113004343541