Base | Representation |
---|---|
bin | 11110000010011111110101… |
… | …101001011010101111001011 |
3 | 122022202212210112112221002021 |
4 | 132002133311221122233023 |
5 | 114304014431201124003 |
6 | 1144551514512545311 |
7 | 36553564542166543 |
oct | 3602376551325713 |
9 | 568685715487067 |
10 | 132113020333003 |
11 | 391058a9886aa6 |
12 | 1299847b252237 |
13 | 5894286c99838 |
14 | 248a43900c323 |
15 | 10418698cc2bd |
hex | 7827f5a5abcb |
132113020333003 has 8 divisors (see below), whose sum is σ = 132291777798000. Its totient is φ = 131934308782080.
The previous prime is 132113020332901. The next prime is 132113020333037. The reversal of 132113020333003 is 300333020311231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132113020333003 - 213 = 132113020324811 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132113020333303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5717878 + ... + 17231371.
It is an arithmetic number, because the mean of its divisors is an integer number (16536472224750).
Almost surely, 2132113020333003 is an apocalyptic number.
132113020333003 is a deficient number, since it is larger than the sum of its proper divisors (178757464997).
132113020333003 is an equidigital number, since it uses as much as digits as its factorization.
132113020333003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22957037.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 132113020333003 its reverse (300333020311231), we get a palindrome (432446040644234).
The spelling of 132113020333003 in words is "one hundred thirty-two trillion, one hundred thirteen billion, twenty million, three hundred thirty-three thousand, three".
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