Base | Representation |
---|---|
bin | 11110000010100000001110… |
… | …010100101111101100101011 |
3 | 122022202220212101120212201121 |
4 | 132002200032110233230223 |
5 | 114304021303143003420 |
6 | 1144552023542400111 |
7 | 36553611030215431 |
oct | 3602401624575453 |
9 | 568686771525647 |
10 | 132113434344235 |
11 | 39105aa1551843 |
12 | 12998575a30037 |
13 | 58943219a56b6 |
14 | 248a477dbcd51 |
15 | 1041890e0c2aa |
hex | 78280e52fb2b |
132113434344235 has 16 divisors (see below), whose sum is σ = 162822301106976. Its totient is φ = 102833344032768.
The previous prime is 132113434344217. The next prime is 132113434344313. The reversal of 132113434344235 is 532443434311231.
It is a cyclic number.
It is not a de Polignac number, because 132113434344235 - 211 = 132113434342187 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132113434344191 and 132113434344200.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18565099 + ... + 24675691.
It is an arithmetic number, because the mean of its divisors is an integer number (10176393819186).
Almost surely, 2132113434344235 is an apocalyptic number.
132113434344235 is a deficient number, since it is larger than the sum of its proper divisors (30708866762741).
132113434344235 is a wasteful number, since it uses less digits than its factorization.
132113434344235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6227502.
The product of its digits is 1244160, while the sum is 43.
Adding to 132113434344235 its reverse (532443434311231), we get a palindrome (664556868655466).
The spelling of 132113434344235 in words is "one hundred thirty-two trillion, one hundred thirteen billion, four hundred thirty-four million, three hundred forty-four thousand, two hundred thirty-five".
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