Base | Representation |
---|---|
bin | 11110000010100000001110… |
… | …010100101111101100011001 |
3 | 122022202220212101120212200221 |
4 | 132002200032110233230121 |
5 | 114304021303143003332 |
6 | 1144552023542400041 |
7 | 36553611030215404 |
oct | 3602401624575431 |
9 | 568686771525627 |
10 | 132113434344217 |
11 | 39105aa1551827 |
12 | 12998575a30021 |
13 | 58943219a56a1 |
14 | 248a477dbcd3b |
15 | 1041890e0c297 |
hex | 78280e52fb19 |
132113434344217 has 2 divisors, whose sum is σ = 132113434344218. Its totient is φ = 132113434344216.
The previous prime is 132113434344149. The next prime is 132113434344313. The reversal of 132113434344217 is 712443434311231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79611077630016 + 52502356714201 = 8922504^2 + 7245851^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132113434344217 is a prime.
It is not a weakly prime, because it can be changed into another prime (132113434354217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66056717172108 + 66056717172109.
It is an arithmetic number, because the mean of its divisors is an integer number (66056717172109).
Almost surely, 2132113434344217 is an apocalyptic number.
It is an amenable number.
132113434344217 is a deficient number, since it is larger than the sum of its proper divisors (1).
132113434344217 is an equidigital number, since it uses as much as digits as its factorization.
132113434344217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 580608, while the sum is 43.
Adding to 132113434344217 its reverse (712443434311231), we get a palindrome (844556868655448).
The spelling of 132113434344217 in words is "one hundred thirty-two trillion, one hundred thirteen billion, four hundred thirty-four million, three hundred forty-four thousand, two hundred seventeen".
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