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132114225515 = 526422845103
BaseRepresentation
bin111101100001010011…
…1110001100101101011
3110122000021020000210112
41323002213301211223
54131032220204030
6140405322204535
712354625250066
oct1730247614553
9418007200715
10132114225515
1151036044048
122173095374b
13c5c5c0364c
1465741b98dd
15368378aa95
hex1ec29f196b

132114225515 has 4 divisors (see below), whose sum is σ = 158537070624. Its totient is φ = 105691380408.

The previous prime is 132114225511. The next prime is 132114225517. The reversal of 132114225515 is 515522411231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 515522411231 = 3116629755201.

It is a cyclic number.

It is not a de Polignac number, because 132114225515 - 22 = 132114225511 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132114225511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13211422547 + ... + 13211422556.

It is an arithmetic number, because the mean of its divisors is an integer number (39634267656).

Almost surely, 2132114225515 is an apocalyptic number.

132114225515 is a deficient number, since it is larger than the sum of its proper divisors (26422845109).

132114225515 is an equidigital number, since it uses as much as digits as its factorization.

132114225515 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26422845108.

The product of its digits is 12000, while the sum is 32.

Adding to 132114225515 its reverse (515522411231), we get a palindrome (647636636746).

The spelling of 132114225515 in words is "one hundred thirty-two billion, one hundred fourteen million, two hundred twenty-five thousand, five hundred fifteen".

Divisors: 1 5 26422845103 132114225515