Search a number
-
+
132114230124133 = 319169146479473
BaseRepresentation
bin11110000010100000111101…
…110000011001111001100101
3122022202222220211222200112011
4132002200331300121321211
5114304024420402433013
61144552234530554221
736553636532224435
oct3602407560317145
9568688824880464
10132114230124133
113910636a76aa84
1212998758438971
13589441a80b78a
14248a51196a2c5
1510418dabedc3d
hex78283dc19e65

132114230124133 has 8 divisors (see below), whose sum is σ = 136377469760256. Its totient is φ = 127851083630400.

The previous prime is 132114230124113. The next prime is 132114230124139. The reversal of 132114230124133 is 331421032411231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132114230124133 - 25 = 132114230124101 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132114230124095 and 132114230124104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132114230124139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20397316 + ... + 26082157.

It is an arithmetic number, because the mean of its divisors is an integer number (17047183720032).

Almost surely, 2132114230124133 is an apocalyptic number.

It is an amenable number.

132114230124133 is a deficient number, since it is larger than the sum of its proper divisors (4263239636123).

132114230124133 is an equidigital number, since it uses as much as digits as its factorization.

132114230124133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46571195.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 132114230124133 its reverse (331421032411231), we get a palindrome (463535262535364).

The spelling of 132114230124133 in words is "one hundred thirty-two trillion, one hundred fourteen billion, two hundred thirty million, one hundred twenty-four thousand, one hundred thirty-three".

Divisors: 1 31 91691 2842421 46479473 1440863663 4261749358843 132114230124133