Base | Representation |
---|---|
bin | 11110000010100001001010… |
… | …100100001101011010000010 |
3 | 122022210000110211101002101022 |
4 | 132002201022210031122002 |
5 | 114304030340411443132 |
6 | 1144552312125105442 |
7 | 36553645052006255 |
oct | 3602411244153202 |
9 | 568700424332338 |
10 | 132114445031042 |
11 | 391064700047a1 |
12 | 129987b83b8282 |
13 | 58944531b4c26 |
14 | 248a53230d09c |
15 | 10418ee9eee12 |
hex | 78284a90d682 |
132114445031042 has 4 divisors (see below), whose sum is σ = 198171667546566. Its totient is φ = 66057222515520.
The previous prime is 132114445031029. The next prime is 132114445031071. The reversal of 132114445031042 is 240130544411231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 109112627598601 + 23001817432441 = 10445699^2 + 4796021^2 .
It is a junction number, because it is equal to n+sod(n) for n = 132114445030993 and 132114445031011.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33028611257759 + ... + 33028611257762.
Almost surely, 2132114445031042 is an apocalyptic number.
132114445031042 is a deficient number, since it is larger than the sum of its proper divisors (66057222515524).
132114445031042 is an equidigital number, since it uses as much as digits as its factorization.
132114445031042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66057222515523.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 132114445031042 its reverse (240130544411231), we get a palindrome (372244989442273).
The spelling of 132114445031042 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-five million, thirty-one thousand, forty-two".
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