Base | Representation |
---|---|
bin | 11110000010100110100100… |
… | …001111000011001111100010 |
3 | 122022210120102222220121112202 |
4 | 132002212210033003033202 |
5 | 114304124230031313442 |
6 | 1144555111413453202 |
7 | 36554241551564615 |
oct | 3602464417031742 |
9 | 568716388817482 |
10 | 132120244401122 |
11 | 3910897666232a |
12 | 12999956641202 |
13 | 5894b68835a63 |
14 | 248a92261417c |
15 | 1041b3dc06c32 |
hex | 7829a43c33e2 |
132120244401122 has 4 divisors (see below), whose sum is σ = 198180366601686. Its totient is φ = 66060122200560.
The previous prime is 132120244401109. The next prime is 132120244401151. The reversal of 132120244401122 is 221104442021231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 130632578750521 + 1487665650601 = 11429461^2 + 1219699^2 .
It is a super-2 number, since 2×1321202444011222 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33030061100279 + ... + 33030061100282.
Almost surely, 2132120244401122 is an apocalyptic number.
132120244401122 is a deficient number, since it is larger than the sum of its proper divisors (66060122200564).
132120244401122 is an equidigital number, since it uses as much as digits as its factorization.
132120244401122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66060122200563.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 132120244401122 its reverse (221104442021231), we get a palindrome (353224686422353).
The spelling of 132120244401122 in words is "one hundred thirty-two trillion, one hundred twenty billion, two hundred forty-four million, four hundred one thousand, one hundred twenty-two".
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