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13212041440042 = 26606020720021
BaseRepresentation
bin1100000001000010101100…
…0010010110101100101010
31201210001120212212202011201
43000100223002112230222
53212431230102040132
644033310020314414
72532352463165524
oct300205302265452
951701525782151
1013212041440042
114234216a57035
1215946b9b42a0a
1374ab758bb233
14339675430a14
1517da1ed152e7
hexc042b096b2a

13212041440042 has 4 divisors (see below), whose sum is σ = 19818062160066. Its totient is φ = 6606020720020.

The previous prime is 13212041439973. The next prime is 13212041440051. The reversal of 13212041440042 is 24004414021231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10387722554001 + 2824318886041 = 3222999^2 + 1680571^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303010360009 + ... + 3303010360012.

Almost surely, 213212041440042 is an apocalyptic number.

13212041440042 is a deficient number, since it is larger than the sum of its proper divisors (6606020720024).

13212041440042 is an equidigital number, since it uses as much as digits as its factorization.

13212041440042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6606020720023.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 13212041440042 its reverse (24004414021231), we get a palindrome (37216455461273).

The spelling of 13212041440042 in words is "thirteen trillion, two hundred twelve billion, forty-one million, four hundred forty thousand, forty-two".

Divisors: 1 2 6606020720021 13212041440042