Base | Representation |
---|---|
bin | 11110000010101000001110… |
… | …111001110111100100101011 |
3 | 122022210202001201101011222021 |
4 | 132002220032321313210223 |
5 | 114304141411201313121 |
6 | 1145000005143205311 |
7 | 36554334112164454 |
oct | 3602501671674453 |
9 | 568722051334867 |
10 | 132122034010411 |
11 | 3910970486a275 |
12 | 1299a175a46837 |
13 | 5895092528473 |
14 | 248aa5218412b |
15 | 1041be5dab641 |
hex | 782a0ee7792b |
132122034010411 has 4 divisors (see below), whose sum is σ = 132322522681800. Its totient is φ = 131921545339024.
The previous prime is 132122034010403. The next prime is 132122034010427. The reversal of 132122034010411 is 114010430221231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132122034010411 - 23 = 132122034010403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132122034010451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100244334706 + ... + 100244336023.
It is an arithmetic number, because the mean of its divisors is an integer number (33080630670450).
Almost surely, 2132122034010411 is an apocalyptic number.
132122034010411 is a deficient number, since it is larger than the sum of its proper divisors (200488671389).
132122034010411 is an equidigital number, since it uses as much as digits as its factorization.
132122034010411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 200488671388.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 132122034010411 its reverse (114010430221231), we get a palindrome (246132464231642).
The spelling of 132122034010411 in words is "one hundred thirty-two trillion, one hundred twenty-two billion, thirty-four million, ten thousand, four hundred eleven".
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