Base | Representation |
---|---|
bin | 11000100111000001… |
… | …01101000101111111 |
3 | 1021002210011110011112 |
4 | 30103200231011333 |
5 | 204024313223203 |
6 | 10023012112235 |
7 | 645261130601 |
oct | 142340550577 |
9 | 37083143145 |
10 | 13212242303 |
11 | 566aa6a217 |
12 | 268890567b |
13 | 1327354370 |
14 | 8d4a17171 |
15 | 524dc86d8 |
hex | 31382d17f |
13212242303 has 4 divisors (see below), whose sum is σ = 14228568648. Its totient is φ = 12195915960.
The previous prime is 13212242299. The next prime is 13212242311. The reversal of 13212242303 is 30324221231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30324221231 = 84809 ⋅357559.
It is a cyclic number.
It is not a de Polignac number, because 13212242303 - 22 = 13212242299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13212242353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508163153 + ... + 508163178.
It is an arithmetic number, because the mean of its divisors is an integer number (3557142162).
Almost surely, 213212242303 is an apocalyptic number.
13212242303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13212242303 is a deficient number, since it is larger than the sum of its proper divisors (1016326345).
13212242303 is a wasteful number, since it uses less digits than its factorization.
13212242303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1016326344.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13212242303 its reverse (30324221231), we get a palindrome (43536463534).
The spelling of 13212242303 in words is "thirteen billion, two hundred twelve million, two hundred forty-two thousand, three hundred three".
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