Base | Representation |
---|---|
bin | 11110000010101000101011… |
… | …011101110110100011000010 |
3 | 122022210210022010001210222101 |
4 | 132002220223131312203002 |
5 | 114304143401340033232 |
6 | 1145000124502101014 |
7 | 36554352021240514 |
oct | 3602505335664302 |
9 | 568723263053871 |
10 | 132122513205442 |
11 | 39109930306621 |
12 | 1299a28a41a76a |
13 | 589513a8a7916 |
14 | 248aa99a81bb4 |
15 | 1041c22eb51e7 |
hex | 782a2b7768c2 |
132122513205442 has 4 divisors (see below), whose sum is σ = 198183769808166. Its totient is φ = 66061256602720.
The previous prime is 132122513205391. The next prime is 132122513205451. The reversal of 132122513205442 is 244502315221231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 117718355336481 + 14404157868961 = 10849809^2 + 3795281^2 .
It is a super-3 number, since 3×1321225132054423 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33030628301359 + ... + 33030628301362.
Almost surely, 2132122513205442 is an apocalyptic number.
132122513205442 is a deficient number, since it is larger than the sum of its proper divisors (66061256602724).
132122513205442 is an equidigital number, since it uses as much as digits as its factorization.
132122513205442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66061256602723.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 132122513205442 its reverse (244502315221231), we get a palindrome (376624828426673).
The spelling of 132122513205442 in words is "one hundred thirty-two trillion, one hundred twenty-two billion, five hundred thirteen million, two hundred five thousand, four hundred forty-two".
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